here it is, not total proof, but some pretty good evidence anyway.
I am here calculating the angle that NASA would have to fire a space probe in order to successfully hit mars. please excuse that my calculations are probably longer than they need to be.
according to (
http://www.nasa.gov/worldbook/mars_worldbook.html) the distance from earth to mars is 33,900,000 (at shortest)
according to the same site the radius of mars is 2107 miles. to give them a bit of room for gravitational pull, we'll tack on another 500 miles. for a total of 2607.
a right triangle is formed with three points
A. a point on earth
B. the center of mars
C. 500 miles from the edge of mars.
since it is a right triangle, and we know two sides (AB, and BC) the pythagorean theorom is used to find the third.
square root of 33,900,000^2+2607^2= 33,900,000.1
now, we use the reversed law of cosines to find the interior angle.
(not posting exact calcs, too difficult with keyboard)
the answer is .0044
when this triangle is reflected across line AB it forms an identical triangle. since the two triangles are the same, the angle A is the same. so .0044+.0044=.0088 which rounded is .01 (try and see that on a protractor)
so NASA would need to launch the mars rover at a tenth of a degree in order to achieve anywhere within 500 miles of mars.
admittedly, these calculations do not take into account correctional systems on the rover, but they also do not account for unpredictable solar wind, meteors, or margins of error in calculations of mars orbit/radius.
It doesn't necessarily prove there is a conspiracy, but you cant even see a hundredth of a degree on a protractor, is it possible that NASA could launch a rover with this kind of accuracy?